Problem and solution math physic 1
This is one of the math physics exam in Jambi University $T=4x-(x^2) $ find coldtest and hottest at point $x=5$ when $y=0 $ $ dT/dx=4-2x=0$ $x=2$ so we have $T=4(2)-(2)^2$ T=4 when $ x=5$ we have $dT/dy =0$ $T=4(5)-(5)^2$ T=-5 $Hottest point is$ $(2,0) is T=4$ $coldtest point is$ $(5,0) is T=-5$